Question

Find the zeros of the quadratic polynomial (x + 5) (X-6).​

Answer 1

Answer:

the zeroes of x2 – 5x + 6 are 3 and 2

Answer 2

Step-by-step explanation:

We have the quadratic polynomial x²+5x+6

splitting the middle term, we get

= x²+2x+3x+6

= x(x+2)+3(x+2)

= (x+2)(x+3)

So, the values of x²+5x+6 is zero when x+2=0 Or x+3=0

i.e ., when x = -2 Or x = -3

Therefore, the zeroes of x²+5x+6 are -2 and -3

Now ,

Verification:

i)the sum of the Zeroes = -2+(-3)

= -5

= (-5)/1

= \frac{-(coefficient\:of \:x)}{coefficient\:of\:x^{2}}

coefficientofx

2

−(coefficientofx)

ii) Product of the zeroes

= (-2)(-3)

= 6

= 6/1

=\frac{(constant\:term)}{coefficient\:of\:x^{2}}

coefficientofx

2

(constantterm)