Question

find the zeros of the quadratic polynomial X square + 7 x + 10 and verify the relation between zeros and coefficient​

Answer 1

GIVEN

p(x)=x^2+7x+10

TO FIND zeros and verify it

SOLUTION

x^2 + 7x + 10 = 0

=> x^2 + 5x + 2x + 10 = 0

=> x(x + 5) + 2(x + 5) = 0

=> (x+5)(x+2) = 0

=> x = -5 or x = -2

VERIFICATION

Sum of zeros = -coefficient of x/coefficient of x^2

=> -5 + -2 = -5 -2 = -7 = - (7/1) = -b/a

Product of zeros = constant/coefficient of x^2

=> -2 × -5 = 10 = 10/1 = c/a

[SOLVED]

Answer 2

x^2 + 7x + 10=0

x^2 + 5x +2x +10 =0

x(x + 5) +2(x + 5) = 0

(x+5) +(x+2) =0

Alfa = -5 and bita = -2

a = 1, b = 7, c = 10

If Alfa = ¶ and bita= ∆

¶+∆= -5-2= -7

-b/a= -7

•°•¶+∆=-b/a

¶∆= (-5)(-2) = 10

c/a= 10

•°•¶∆=c/a

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