find the zeros of the quadratic polynomial X square + 7 x + 10 and verify the relationship between the zeros and coefficient
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Answered by
37
x²+5x+2x+10
x(x+5)+2(x+5)
(x+2)(x+5)
x=-2 x=-5
it's ur ans. plz mark as brainlist
x(x+5)+2(x+5)
(x+2)(x+5)
x=-2 x=-5
it's ur ans. plz mark as brainlist
buldoze:
thanx a lot
Answered by
41
x²+7x+10=0
=>x²+2x+5x+10=0
=>x(x+2)+5(x+2)=0
=>(x+2)(x+5)=0
therefore
x=-2, -5 that is zero of the eqsn...
now verify.....
sum of the zeroes=>-2-5=-7(-x coefficient)/1 x² coefficient)
product of zeroes =>-2×(-5)=10 constant turn /1 x² coefficient.
now.... finished plz give me brainlist marks.
ok my dear
=>x²+2x+5x+10=0
=>x(x+2)+5(x+2)=0
=>(x+2)(x+5)=0
therefore
x=-2, -5 that is zero of the eqsn...
now verify.....
sum of the zeroes=>-2-5=-7(-x coefficient)/1 x² coefficient)
product of zeroes =>-2×(-5)=10 constant turn /1 x² coefficient.
now.... finished plz give me brainlist marks.
ok my dear
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