Question

find the zeros of the quadratic polynomial X square + 8 x + 15 and verify the relationship between the zeros and the coefficient​

Answer 1

explanation:

x²+8x+15

x²+3x+5x+15

x(x+3)+5(x+3)

(x+3)(x+5)

x+5=0

x+3=0

x=-5

x=-3

Therefore,zeroes of the polynomial are -5,-3.

sum of zeros =-3-5

=-8

I hope that it will help you.Thank you.

Answer 2

The correct answer is Sum of roots = -8 and product of roots = 15.

Given: $x^{2} +8x+15=0$

To Find: Zeroes of this equation.

Solution:

The zeroes or roots of equation are the one which satisfy the equation.

$x^{2} +8x+15=0$

By middle term splitting

$x^{2} +3x+5x+15$

$x(x+3)+5(x+3)\\ (x+3)(x+5)$

x = -3, -5

So, the zeroes of this equation are -3 and -5.

In equation ax + by + c = 0

Sum of roots = $\frac{-b}{a}$

= $\frac{-8}{1}$

= -8

Hence, in this equation sum of roots is -8.

Product of roots = $\frac{c}{a}$

= $\frac{15}{1}$

= 15

Hence, in this equation product of roots is 15.

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