Question

Find the zeros of the quadratic polynomial x square + 89 x + 720

Answer 1

≡QUESTION≡

Find the zeros of the quadratic polynomial

$x^{2} +89x+720=0$

                                                     

║⊕ANSWER⊕║

Given equation

$x^{2} +89x + 720 = 0$

Solving, we get,

$=>x^{2} +80x+9x+720 = 0$

$=>x(x+80)+9(x+80)=0$

$=>(x+9)(x+80)=0$

Now,

$x+9=0\\=> x = -9$

$x+80 = 0\\=> x = -80$

∴ Zeroes of the polynomial are -9 and -80.

                                                         

Answer 2

Answer:

Given equation

x^{2} +89x + 720 = 0x

2

+89x+720=0

Solving, we get,

= > x^{2} +80x+9x+720 = 0=>x

2

+80x+9x+720=0

= > x(x+80)+9(x+80)=0=>x(x+80)+9(x+80)=0

= > (x+9)(x+80)=0=>(x+9)(x+80)=0

Now,

\begin{gathered}x+9=0\\= > x = -9\end{gathered}

x+9=0

=>x=−9

\begin{gathered}x+80 = 0\\= > x = -80\end{gathered}

x+80=0

=>x=−80

∴ Zeroes of the polynomial are -9 and -80.