Find the zeros of the quadratic polynomial x square minus 2 and verify the relationship between the zeros and the coefficients
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Step-by-step explanation:
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Answer:
The solutions for x are √2 and -√2.
Step-by-step explanation:
using (a^2-b^2) = (a+b)(a-b),
(x^2-2) can be written as ( x-√2 )( x+√2)
equating ( x-√2 ) to 0,
x-√2=0, therefore x = √2
equating ( x+√2) to 0,
x+√2=0, therefore x = - √2
∴ α = √2
β = - √2
a = 1, b = 0, c = -2
so we get: α+β= -b/a, α*β=c/a after substituting the values
Hope this helped you.... =))
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