Question

find the zeros of the quadratic polynomial x square minus 2 root 2 X and verify the relationship between the zeros and the coefficients​

Answer 1

Answer:

Step-by-step explanation:

x^2-2√2x=0

x(x-2√2)=0

x=0

x-2√2=0

x=2√2

zeros are

α= 0

β= 2√2

•relation between zeros and coefficient where a= 1, b=-2√2,c=0

•α+β= -b/a

0+2√2=2√2

=-b/a= -(-2√2)/1

=2√2

•α*β=c/a

0*2√2=0

c/a = 0/1=0

hence both the relations are verified

Answer 2

$\blue{\mathbb{ANSWER}}$

x²-2√2x = 0

x(x-2√2)= 0

x = 0 x = 2√2

We know that ,

α+β = $\frac{-b}{a}$

αβ = $\frac{c}{a}$

$\huge{VERIFICATION}$

Here, a = 1 , b = -2√2 and c = 0

Sum-

0 + 2√2= -(-2√2)/1

2√2 = 2√2

Product -

0 × 2√2 = 0/1

0 = 0

Hence Verified