Question

Find the zeros of the quadratic polynomial x square +rx+10 and verify the relationship between the zeros and the co-efficients

Answer 1

Step-by-step explanation:

${x}^{2} + rx + 10$

is in the form of

$a {x}^{2} + bx + c$

$a = 1 \\ b = r \\ c = 10$

let

$\alpha \: and \: \beta$

be roots of quadratic equation

Sum of roots

$\alpha + \beta = \frac{ - b}{a} \\ = \frac{ - r}{1} = - r$

Product of roots

$\alpha \times \beta = \frac{c}{a} \\ = 10$