Question

find the zeros of the quadratic polynomial x2+3x-10 by completing the square method​

Answer 1

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HERE IS YOUR ANSWER:

STEP BY STEP EXPLANATION:

Answer 2

$\textbf{\large{\pink{\underline{\underline{Step by step Explanation:-}}}}}$

$\mathrm{x^{2}+3x-10=0}$

$\mathrm{\implies{x^{2}+2\times{x}\times{\frac{3}{2}}+(\frac{3}{2})^{2}-10=0+(\frac{3}{2})^{2}}}$

$\mathrm{\implies{(x+\frac{3}{2})^{2}-10=\frac{9}{4}}}$

$\mathrm{\implies{(x+\frac{3}{2})^{2}=\frac{9}{4}+10}}$

$\mathrm{\implies{(x+\frac{3}{2})^{2}=\frac{9+40}{4}}}$

$\mathrm{\implies{(x+\frac{3}{2})^{2}=\frac{49}{4}}}$

$\mathrm{\implies{x+\frac{3}{2}=\pm \sqrt{\frac{49}{4}}}}$

$\mathrm{\implies{x+\frac{3}{2}=\pm \frac{7}{2}}}$

$\mathrm{\implies{x=\frac{-3}{2}\pm \frac{7}{2}}}$

$\mathrm{x=\frac{-3}{2}+ \frac{7}{2}}$

$\mathrm{\implies{x=\frac{-3+7}{2}}}$

$\mathrm{\implies{x=\frac{4}{2}}}$

$\mathrm{\implies{x=2}}$

$\mathrm{or,,x=\frac{-3}{2}- \frac{7}{2}}$

$\mathrm{\implies{x=\frac{-3-7}{2}}}$

$\mathrm{\implies{x=\frac{-10}{2}}}$

$\mathrm{\implies{x=-5}}$

$\textit{\underline{Hence,,}}$

$\mathrm{\implies{\blue{\boxed{x= 2,,0r,,-5}}}}$

❣️❣️$\textbf{\small{\green{\underline{Hope it helps you}}}}$❣️❣️

$\textit{\small{\red{\underline{Please mark it as Brainliest answer..thanks}}}}$