Question

Find the zeros of the quadratic polynomial (x²-3x+2)​

Answer 1

Answer:

1 and 2

Step-by-step explanation:

By middle term splitting -

$f(x) = \: {x}^{2} - 3x + 2 = 0\\ = > {x}^{2} - 2x - x + 2 = 0\\ = > x(x - 2) - 1(x - 2) = 0 \\ = > (x - 2)(x - 1) = 0$

Hence, x -2 = 0 => x = 2

OR

x -1 = 0 => x = 1