Find the zeros of the quadratic polynomial x2
– 7 and verify the relationship
between the zeros and the coefficients
Answers
Answer:
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Given : quadratic polynomial x² - 7
To Find :zeros
and verify the relationship between the zeros and the coefficients
Solution:
polynomial x² - 7
to find zero Equate the polynomial with zero
Hence x² - 7 = 0
=> x² = 7
=> x = ±√7
Hence zeroes are +√7 , - √7
P(x) = ax² + bx + c
Sum of zeros = - b/a
Product of zeroes = c/a
x² - 7 compare with ax² + bx + c
a = 1 , b = 0 , c = -7
Sum of zeroes = - 0/1 = 0
Sum of zeroes = +√7 - √7 = 0
Hence verified
Product of zeroes = -7/1 = - 7
Product of zeroes = +√7 * (- √7) = -7
Hence Verified
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