Question

Find the zeros of the quadratic polynomial x2 + 7x +10 and
verify the relationship between the zeros and the coefficients.
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Answer 1

Step-by-step explanation:

Given : x² + 7x + 10

x² + 7x + 10

x² + 2x + 5x + 10

x(x + 2) + 5 ( x + 2)

( x + 2) ( x + 5)

So, x = - 2, - 5

Relationship

Sum of zeroes = -b/a = - 7/1

- 2 - 5 = - 7

Product of zero = 10

(-2) × (-5) = 10

Answer 2

Answer:

Given : x² + 7x + 10

x² + 7x + 10

x² + 2x + 5x + 10

x(x + 2) + 5 ( x + 2)

( x + 2) ( x + 5)

So, x = - 2, - 5

Relationship

Sum of zeroes = -b/a = - 7/1

- 2 - 5 = - 7

Product of zero = 10

(-2) × (-5) = 10

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