Question

Find the zeros of the quadratic polynomial x2+7x+2​

Answer 1

Explanation:

Heya !!

Given :-

• x^2+7x+2

To Find :-

• the zeros of the quadratic polynomial

Solution :-

We have

x = - b ± √ b^2- 4ac /2a

Applying ax^2 + bx + c

a = 1 , b = 7, c = 2

x = - 7 ± 7^2 - 4 × 1 × 2 / 2 × 1

x = - 7 ± 49 - 8 /2

x = - 7 ± 41 / 2

Hence x = - 7 + 41 / 2

x = - 7 - 41 / 2

Answer 2

Answer:

X^2 +7x +2

X = -b +- √ b^2 -4ac /2a

X = -7+-√(7)^2 -4*1*2/2*1

X = -7+-√ 49-8/2

X = -7+-√41/2

X = -7+√41/2 , -7-√41/2

Hope it help you ✌️❣️