Question

Find the zeros of the quadratic polynomial X2 + X - 12 and verify the relationship between zeros and coefficient

Answer 1

Answer:

Hey Mate

Here Is Your Answer

x^2+x-12=0

(x^2-3x)(+4x-12)=0

x(x-3)+4(x-3)=0

(x-3)(x+4)=0

x-3=0 x+4=0

x=3 x=-4

$\alpha = 3 \\ \beta = - 4 \\ \alpha + \beta = \frac{ - b}{a} \\ 3 - 4 = - 1 \div 1 \\ - 1 = - 1 \\ \alpha \times \beta = \frac{c}{a} \\ 3 \times - 4 = - 12 \\ - 12 = - 12$

Hope It Helps

MARK IT AS BRAINLIEST

REGARDS

GUNJAN