Question

Find the zeros of the quadratic polynomials of the given equation and verify the relationship between the coefficients and zeros. Use
$\alpha \: and \: \beta$
4u² + 8u​

Answer 1

GIVEN:

Quadratic polynomial = 4u² + 8u

TO FIND:

Zeroes and verify the relationship between the coefficients and zeros.

SOLUTION:

4u² + 8u = 0

4u(u + 2) = 0

4u = 0 ; u + 2 = 0

u = 0 ; u = -2

The zeroes of polynomial are 0 and -2

VERIFICATION:

Sum of zeroes = 0 + (-2) = -2

Product of zeroes = 0 × -2 = 0

Using coefficients,

Sum of zeroes = -b/a = -8/4 = -2

Product of zeroes = c/a = 0/4 = 0

Hence, verified!

Answer 2

Answer:

Step-by-step explanation:

Given :-

Given Quadratic Polynomials = 4u² + 8u

To Find :-

Zeros of the quadratic polynomials and verify the relationship between the coefficients and zeros.

Solution :-

⇒ p(x) = 4u²+8u

⇒  4u(u + 2) = 0

⇒ (4u + 0)(u + 2) = 0

⇒ u = 0 , u = -2

Here ,  a = 4  , b = 8  , c = 0

Now, Relation between zeros and its coefficients

Sum of zeroes = 0 + (- 2) = - 2

= -b/a = - 8/4 = - 2

Product of zeroes = 0 x (- 2) = 0

= c/a = 0/4 = 0

Hence, Verified.