Find the zeros of the quadratic polynomialx2+7x+12 and verify the relationship between the zeros and its coefficient
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x²+7x+12
=x²+3x+4x+12
=x(x+3)+4(x+3). [taking common]
=(x+4)(x+3)
=x+4=0 so x=-4 & x+3=0 so x=-3
So, zeroes of the quadratic equations are -3 and -4
You can put any value (either -3 or -4) to verify the result.
Hope, you will like the answer
=x²+3x+4x+12
=x(x+3)+4(x+3). [taking common]
=(x+4)(x+3)
=x+4=0 so x=-4 & x+3=0 so x=-3
So, zeroes of the quadratic equations are -3 and -4
You can put any value (either -3 or -4) to verify the result.
Hope, you will like the answer
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