Find the zeros of the quadric polynomial 4x²-4x+1 adn verify the relationship between the zeros and the coefficients
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Step-by-step explanation:
||✪✪ QUESTION ✪✪||
Find the zeroes of the quadratic polynomial 4x²-4x+1 and verify the relation between its zeroes and coefficients ?
|| ✰✰ ANSWER ✰✰ ||
Given , quadratic polynomial is 4x²-4x+1.
To Find The Number of Zeros Put The polynomial Equals to 0 First.
→ 4x² - 4x + 1 = 0
Now, Splitting The Middle Term , we get,
→ 4x² - 2x - 2x + 1 = 0
→ 2x(2x - 1) - 1(2x - 1) = 0
→ (2x - 1)(2x - 1) = 0
Putting Both Equal to Zero now, we get,
→ 2x - 1 = 0
→ 2x = 1
→ x = (1/2)
Hence, Both Zeros of Quadratic Equation Are (1/2).
____________________________
Now, First Relation is :-
→ Sum of Zeros = - (coefficient of x) /(coefficient of x²)
Putting both values ,
→ (1/2 + 1/2) = -(-4)/4
→ 1 = 1 ✪✪ Hence Verified. ✪✪
Second Relation :-
→ Product Of Zeros = Constant Term / (coefficient of x²)
Putting both Values ,
→ (1/2) * (1/2) = (1) / (4)
→ 1/4 = 1/4 ✪✪ Hence Verified. ✪✪
_____________________________
Answered by
0
Answer:
1/4 = 1/4 is the answer mate
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