Question

find the Zeros of the quadric polynomial (8x^2-4) ans verify relationship between the zeroes and the coefficients.​

Answer 1

Answer:

(8x^2-4)

4 (2x^2-1)

4 (root2+1)(root2-1)

Zeros=-root2 or root2

alpha+beta=-root2+root2=0

alpha/beta=-root2×root2=-2

OR

alpha+ beta=-b/a=0/-4=0

alphabeta=c/a=-8/4=-2

I HOPE THIS HELPS

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