find the Zeros of the quadric polynomial (8x^2-4) ans verify relationship between the zeroes and the coefficients.
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Answer:
(8x^2-4)
4 (2x^2-1)
4 (root2+1)(root2-1)
Zeros=-root2 or root2
alpha+beta=-root2+root2=0
alpha/beta=-root2×root2=-2
OR
alpha+ beta=-b/a=0/-4=0
alphabeta=c/a=-8/4=-2
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