Question

Find the zeros of the quardic polynomial 6x^2 - 3 and verify the relationship between the zeros and co efficient​

Answer 1

Answer:

Hello

Step-by-step explanation:

$6x^{2} - 3$ = 0

$3(2x^{2} - 1) =0$

$2x^{2} - 1 =0$

$2x^{2} =1\\x^{2} = 1/2\\x = \sqrt{1/2}$

Hence , the zero of the quadratic polynomial is $x = \sqrt{1/2}$

Verify the relationship between the zeros and co efficient​ :

a = 6 , b = 0 , c = 3

sum of zeroes = -b/a

                        = 0

product of zeroes = c/a

                               =  3/6

                               =1/2

sum of zeroes  =  $\sqrt{1/2} + (- \sqrt{1/2})$

                         = 0

product of zeroes = $\sqrt{1/2} * \sqrt{1/2}$

                               =$1/2$

Hence , as all the results are equal , the relation is verified.

:)