find the zeros of the qudratic polynomial x^2+7x +10 and verify the relationship between the zeros and it's coefficient
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Answer:x²+7x+10=0
x²+2x+5x+10=0
x(x+2)+5(x+2)=0
(x+2)(x+5) = 0
x+2 = 0 ; x = -2
x+5 = 0 ; x = -5
Relationship between the zeroes and coefficients :-
Sum of zeroes = -2+(-5) = -2-5
= -7/1 = -x coefficient /x² coefficient
Product of zeroes = (-2)(-5)
= 10/1 = constant/x² coefficient
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