Question

find the zeros of the t2-15 quadratic polynomials and verify the relationship between the zeros and the coefficients. ​

Answer 1

Step-by-step explanation:

the question is descriptively solved hereby.

Answer 2

Answer:

${t}^{2} - 15 = 0$

${t}^{2} = 15$

${t}^{2} = + - \sqrt{15}$

$product \: of \: roots \: = \frac{c}{a}$

$+ \sqrt{15} \times - \sqrt{15} = \frac{ - 15}{1}$

$- 15 = - 15$

$sum \: of \: roots = \frac{ - b}{a}$

$- \sqrt{15} + \sqrt{15} = \frac{0}{1}$

$0 = 0$