Question

find the zeros of thequadratic polynomial (6x^2-3-7x) and find the relation between the zeros and coefficient​

Answer 1

Answer:

$hi \: friend \: here \: is \: your \: answer.. \\ 6 {x}^{2} - 3 - 7x \\ so.. \\ we \: can \: write \: it \: in \: its \: form \\ 6 {x}^{2} - 7x - 3 \\ 6 {x}^{2} - 9x + 2x - 3 \\ 3x(2x - 3) + 1(2x - 3) \\ (3x + 1)(2x - 3) \\ 3x + 1 = 0 \: \: \: and \: \: 2x - 3 = 0 \\ x = \frac{1}{3} \: \: \: or \: x = \frac{3}{2}$

hope it helps you...