Math, asked by imoksha105, 3 months ago

find the zeros of this polynomial​

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Answered by Anonymous
1

Answer:

p (y) = y² + 3√5y/2 - 5

» y² + 3√5y/2 - 5 = 0

» 2y² + 3√5y - 10 = 0

» 2y² + 4√5y - √5y - 10 = 0

» 2y (y + 2√5) - √5 (y + 2√5) = 0

» (y + 2√5) (2y - √5) = 0

» y = -2√5 or √5/2

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