Question

find the zeros of this polynomial p(x)=(x+2)(2x^2+3x-9)p(x)=(x+2)(2x2+3x−9)​

Answer 1

Given:

The expression, p(x) = (x + 2) (2x^2 + 3x - 9)

To find:

Find the zeros of this polynomial p(x) = (x + 2) (2x^2 + 3x - 9)

Solution:

From given, we have.

The expression, p(x) = (x + 2) (2x^2 + 3x - 9)

In order to find the zeros of the given expression equate it to zero

p(x) = (x + 2) (2x^2 + 3x - 9)

p(x) = 0

(x + 2) (2x^2 + 3x - 9) = 0

Consider the first term,

⇒ (x + 2) = 0

x = -2

Consider the second term,

⇒ (2x^2 + 3x - 9) = 0

(x + 3) (2x - 3) = 0

x + 3 = 0 ⇒ x = -3

2x - 3 = 0 ⇒ x = 3/2

Therefore, the zeros of the polynomial are -2, -3 and 3/2

Answer 2

please mark me as brainliest