Question

Find the zeros of (x-2)^2+4
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Answer 1

Answer:

IT'S (X-2)^2 + 4 = 0

X^2+(2)^2-2 (X)(2)+4 =0

X^2 +4 -4X +4 =0

X^2-4X +8 =0.

NOW, YOU FIND OUT THE ZEROES EASILY.

HOPE IT HELPS YOU :)

please mark my answer brainliest dear...❤

Answer 2

Answer:

Hi Friend !!!!

Here is ur answer !!!

(x-2)²+4

= x²+2²-4x+4

= x²-4x+8

discriminant, Δ= b²-4ac

=(-4)²-4(1)(8)

= 16-32

= -16

so, this polynomial has no real zeroes

Hope it helps u : )