Question

find the zeros of (x-2) ^2-(x+2) ^2​

Answer 1

Answer:

find the zeros of (x-2) ^2-(x+2) ^2

Answer 2

HEY MATR HERE'S YOUR ANSWER

$p(x) = (x - 2 )^{2} - (x - {2})^{2} \\ \\ in \: this \: form \: of \: {a}^{2} - {b}^{2} \\ p(x) = (x - 2 + x + 2)(x - 2 - (x + 2)) \\ p(x) = 2x(x - 2 - x - 2) \\ p(x) = 2x - 4 \\ p(x) = 0 \\ - 8 = 0 \\ x = 0 \\ hence \\ x = 0 \: is \: the \: zero \: of \: the \: polynomial \: p(x)$

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