Question

Find the zeros of x^2-2x-8

Answer 1

Step-by-step explanation:

$2 - 2x - 8 = 0 \\ 2x - 6 = 0 \\ 2x = 6 \\ x = \frac{6}{2 } \\ x = 3$

Answer 2

Given :-

${x}^{2} - 2x - 8 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

${x}^{2} - 2x - 8 = 0 \\ \\ {x}^{2} - 4x + 2x - 8 = 0 \\ \\ x(x - 4) + 2(x - 4) = 0 \\ \\ (x - 4)(x + 2) = 0$

Now split it into possible cases

$(x - 4) = 0 \\ \\ (x + 2) = 0$

Hence,

$x _1 = (4) \\ \\x _2 = ( - 2)$

Extra information :-

• An equation containing a single variable of degree 2. Its general form is ax^2 + bx + c = 0, where x is the variable and a, b, and c are constants (a ≠ 0).