Question

find the zeros of x^2-3

Answer 1

$p(x) = 0 \\ {x}^{2} - 3 = 0 \\ {x}^{2} = 3 \\ x = + \sqrt{3} \: \: \: \: or \: - \sqrt{3} \\ \\ \\ so \: + \sqrt{3 } and \: - \sqrt{3} \: are \: the \: zeroes \\ of \: the \: given \: polynomial.$

⭐hope it may help you⭐

Answer 2

$\huge \text {Solution}$


$= > {x}^{2} - 3 \\ so \\ = > {x}^{2} - 3 = 0 \\ = > {x}^{2} = 3 \\ = > x = 3 \: answer$


$\huge {Be} ^ {Brainly}$