Question

Find the zeros of (x-2)^3-(x+2)^2​

Answer 1

Answer:

PLEASE MARK BRAINLIEST

Step-by-step explanation:

"Zero

Given polynomial equation is,

p(x) = (x-2)^2 - (x+2)^2p(x)=(x−2)2−(x+2)2

Let us expand the equation to simplify it.

Expand (x-2)^2 and (x+2)^2.(x−2)2and(x+2)2.

Such that,

p(x) = (x^2 - 4x + 4) - (x^2 + 4x + 4)p(x)=(x2−4x+4)−(x2+4x+4)

   = x^2 - 4x + 4 - x^2 - 4x - 4=x2−4x+4−x2−4x−4

      = -8x

At x = 0, p(x) = -8x = -8×0 = 0

Since p(x) equations does not exist any constants

Therefore, it results zero."