Find the zeros of (x^2-4)-(x+2)^2
Answers
Answered by
2
Answer: There is only one zero – α = - 2.
Equation:
(x² - 4) - (x + 2)² = 0
=> (x + 2)(x - 2) - (x + 2)(x + 2) = 0
=> (x + 2)[(x - 2) - (x + 2)] = 0
=> x + 2 = 0
=> x = - 2.
Answered by
0
Step-by-step explanation:
(X+X=0 is simpl yar just
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