Question

Find the zeros of x^2+x-2

Answer 1

Step-by-step explanation:

x^2+x-2=0

x^2+(2-1)x-2=0

x^2+2x-x-2=0

x(x+2)-1(x+2)=0

(x+2)(x-1)=0

x=-2,x=1

Answer 2

Answer:

p(-2)=0

Step-by-step explanation:

p(x)=x^2+x-2

p(-2)=(-2)^2+(-2)-(-2)

= 4-2-2

= 4 - 4

= 0

hope it is correct