Find the zeros of (x-3)²+5.
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Answer:
2,4
Step-by-step explanation:
x²-6x +3 +5 =0
x²-6x+8 =0
x²-4x-2x+8 =0
x(x-4)-2(x-4) =0
(x-2) (x-4) =0
This shows that,
x-2 =0 or x-4=0
x=2 or x=4
So, x=2,4
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