Math, asked by Chikkudusumith, 10 months ago

Find the zeros of x square - 2 x minus 8

Answers

Answered by vaishnavitiwari1041
4

Answer:

Here's your answer

 {x}^{2}  - 2x - 8 \\  \\  {x}^{2}  - 4x + 2x - 8 = 0 \\  \\ x(x - 4) + 2(x - 4) = 0 \\  \\ (x - 4)(x + 2) = 0 \\  \\ so \: zeroes \: are \:  \\  \\ x =

x = 4 \: and \:   - 2

Hope it helps

Answered by abc420
1

Step-by-step explanation:

Let, p(x) =0

x2-2x-8=0

We find root using splitting the middle term method

x2-4x+2x-8=0

x(x-4)+2(x-4)=0

(x+2)(x-4)=0

So, x= -2 , 4

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