Question

Find the zeros of x²+1/6x-2
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Answer 1

Answer:

So the zeroes of the polynomial are 4/3 and -3/2.

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Answer 2

Step-by-step explanation:

ax^2+bx+c=0

a=1,b=1/6,c=-2

-b+√(b^2-4ac)/2a or -b-√(b^2-4ac)/2a

-1/6+√(1/6^2-4(-2))/2 or -1/6-√(1/6^2-4(-2))/2

simplify, we get ans of this