find the zeros of x2-25
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x square -25
=x square -5square
=(x-5)(x+5)
x=5and x=-5
=x square -5square
=(x-5)(x+5)
x=5and x=-5
Answered by
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x^2 - 25
= > x^2 - 5^2
we know that a^2 - b^2 = (a+b) (a-b)
=> (x + 5 ) (x - 5)
x +5 = 0 x - 5 = 0
x = -5 x = 5
So the two zeroes are 5 and -5.
= > x^2 - 5^2
we know that a^2 - b^2 = (a+b) (a-b)
=> (x + 5 ) (x - 5)
x +5 = 0 x - 5 = 0
x = -5 x = 5
So the two zeroes are 5 and -5.
delishasharma4:
thank you so mucj
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