Question

find the zeros of x²+3√2x+4​

Answer 1

Answer:

$-2\sqrt{2}, -\sqrt{2}$

Step-by-step explanation:

$x^{2} + 3\sqrt{2} x + 4\\x^{2} + 2\sqrt{2} x + \sqrt{2} x + 4\\x(x+2\sqrt{2} ) + \sqrt{2} (x + 2\sqrt{2})\\(x+2\sqrt{2} )(x+\sqrt{2})\\\\x = -2\sqrt{2} , -\sqrt{2}$