Question

find the zeros of x² +7x+12​

Answer 1

Step-by-step explanation:

let p(x) = x² + 7x + 12

to find zeros, equate p(x) to zero and solve

x² + 7x + 12 = 0

=> x² + 4x + 3x + 12 = 0

=> x(x + 4) + 3(x + 4) = 0

=> (x + 4)(x + 3) = 0

=> x + 4 = 0 => x = -4

=> x + 3 = 0 => x = -3

therefore two zeros are -3 and -4