find the zeros of x2+(a+1/a)X+1
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Step-by-step explanation:
Given that:-
P(x)=x²+(a+1/a)X+1
=>P(x)=x²+ax+(1/a)x+1
=>P(x)=x²+ax+(1/a)x+(a×1/a)
=>P(x)=x(x+a)+(1/a)(x+a)
=>P(x)=(x+a)(x+(1/a))
To get zeroes we can write P(x)=0
=>(x+a)(x+(1/a))=0
=>x+a=0 or (x+(1/a))=0
=>x=-a or x=-1/a
Zeroes of the given polynomial are -a and -1/a
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