Math, asked by mysterioX, 4 months ago

find the zeros of x2+(a+1/a)X+1​

Answers

Answered by tennetiraj86
2

Step-by-step explanation:

Given that:-

P(x)=+(a+1/a)X+1

=>P(x)=x²+ax+(1/a)x+1

=>P(x)=+ax+(1/a)x+(1/a)

=>P(x)=x(x+a)+(1/a)(x+a)

=>P(x)=(x+a)(x+(1/a))

To get zeroes we can write P(x)=0

=>(x+a)(x+(1/a))=0

=>x+a=0 or (x+(1/a))=0

=>x=-a or x=-1/a

Zeroes of the given polynomial are -a and -1/a

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