Question

find the zeros of y^2-4,verify the relationship between zeroes and coefficients​

Answer 1

Answer:

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Answer 2

Answer:

${y}^{2} - 4 = 0 \\ {y}^{2} = 4 \\ y = 2 \: \: \: or \: - 2 \\ now \: the \: relation \: of \: zeroes \: and \: coeficents \: are \: \\ \alpha + \beta = - (b \div a) \\ - (2 + 2) = 0\\ and \: \alpha \beta \: = - 2 \times 2 \\ = - 4$