Question

find the zeros of3x2-x-4​

Answer 1

Answer:

3x²-x-4

3x²-4x+3x-4

x(3x-4)+1(3x-4)

(3x-4)(x+1)

So zeros of the quadratic equation are either 4/3 or –1

Answer 2

Answer:

$hey \: mate \: your \: answer \: is \: \\ =p(0) = 3 {x}^{2} - x - 4 \\ p(0) = 3 ({0}^{2} ) - 0 + 4 \\ = p(0) = 0 - 0 + 4 \\ = p(0) = 4..... \\ hope \: its \: helps.....$