Question

find the zeros. ofquartic expprssion x2+8x+12​

Answer 1

Answer:

x=-6,-2

Step-by-step explanation:

x²+8x+12

x²+2x+6x+12(as 6 and 2 are factors of 12)

x(x+2)+6(x+2)

(x+6)(x+2)

x=-6,-2

Answer 2

Answer:

$x^{2}+8x+12 =0\\ x^{2} +6x+2x+12=0\\x(x+6) +2(x+6)=0\\(x+2)(x+6)=0\\x=-2 \\x=-6$

hence the zeroes of this quadratic expression are -2 and -6.