Question

find the zeros P(x) = 3x² + 2x-1​

Answer 1

Answer: -1

Step-by-step explanation:

x + 1 = 0

x = -1

3(-1)^2 + 2(-1) - 1

=3 - 2 - 1

=0

Answer 2

Answer:

The zeroes are 1/3 and -1

Step-by-step explanation:

$p(x) = 3 {x}^{2} + 2x - 1 \\ \: \: \: \: \: \: \: \: \: \: = 3 {x}^{2} + 3x - 1x - 1 \\ \: \: \: \: \: \: \: \: \: \: = 3x(x + 1) - 1(x + 1) \\ \: \: \: \: \: \: \: \: \: \: = (3x - 1)(x + 1) \\ \: \: \: \: \: \: \: \: \: \: = 3x - 1 = 0 \: \: \: x + 1 = 0 \\ \: \: \: \: \: \: \: \: \: \: = x = \frac{1}{3} \: \: \: x = - 1$