Find the zeros
p(x)=
g(x)=
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Answer:
Step-by-step explanation:
X^2+2√2x-6
X^2+3√2x-√2x-6
X(x+3√2)-√2(x+3√2)
X=√2,-3√2
Multiply a(x^2+1)=ax^2+a
-x(a^2+1)=-xa^2-x
Place like terms together
ax^2-xa^2+a-x
ax(x-a)-1(x-a)
(ax-1)(x-a)
x=1/a,a
Hope you will get!!
Mark it as brainlist pls
priyanshu7777:
1)- ax(sq)+a - xa(sq)+x.........2)- ax(sq)-xa(sq)+a+x.......3)- ax(x-a) -1(a-x)........4)- (ax+1)(x-a)..... 5) ax=1 x=a...6) x=1/a AND x=a
this is the right way I think
try and aslo edit
OK
yes now it is correct
thank you
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