Question

Find the zeros, the sum and the product of zeros of p(x)=4x²+12x+5.

Answer 1

this is the answer hope it will help you

Answer 2

$Your \: answer$

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$p (x) = 4 {x}^{2} + 12x + 5 \\ \\ 4{x}^{2} + 2x + 10x + 5 = 0 \\ \\ 2x ( 2x + 1 ) + 5 ( 2x + 1 ) = 0 \\ \\ 2x + 5 = 0 , 2x + 1 = 0 \\ \\ x = \frac{-5}{2} , x = \frac{-1}{2} \\ \\ Sum \: of \: zeroes = \frac{-5}{2} + \frac{-1}{2} \\ \\ \frac{-6}{2} \\ \\ -3 \\ \\ Product \: of \: zeroes = \frac{-5}{2}(\frac{-1}{2}) \\ \\ \frac{+5}{4}$