Question

find the zeros
v²+4√3v-15

Answer 1

Hey there !!

f(v) =v²+4√3v-15

splitting middle term :-

v²+5√3v-√3v-15

= v(v+5√3) - √3 (v+5√3)

= (v-√3) (v+5√3)


Hence ,
√3, -5√3 are the zeros of the given polynomial.

Answer 2

Given:

v²+4√3v-15

To find:

The zeroes

Solution:

The required zeroes are √3 and -5√3.

We can factorize the given expression and obtain the equation's roots.

The given equation: v²+4√3v-15

We will express it as follows-

=v²+4√3v-15

=v²+5√3v-√3v-15

Now we will take out the common values.

=v(v+5√3)-√3(v+5√3)

=(v+5√3)(v-√3)

We will equate these brackets to 0 to get the roots.

(v+5√3)=0

v= -5√3

(v-√3)=0

v=√3

So, zeroes are √3 and -5√3.

Therefore, the required zeroes are √3 and -5√3.