Question

find the zeros
X²-13x+36
​

Answer 1

Answer:

4 and -9

Step-by-step explanation:

$x^{2} -13x+36$

It can be factorised as follows using splitting the middle term

$x^{2} -4x-9x+36\\= x(x-4)+9(x-4)\\=(x+9)(x-4)$

Zeroes are:

x + 9 = 0

x = -9

x-4 = 0

x = 4