find the zeros
y²+3/2√5y-5
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y2 + 3√5/2y - 5 = 0
2y2 + 3√5y - 10 = 0
2y2 + (4√5y - √5y) - 10 = 0
2y2 + (4√5y - √5y) - 10 = 0
2y(y + 2√5) - √5(y + 2√5) = 0
(y + 2√5)(2y - √5) = 0
⇒ y = - 2√5.
, √5
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