Question

find the zeross of the polynomial x2-3 and verify the relationship between the zeros and coefficients ​

Answer 1

Step-by-step explanation:

x²-3 = 0

x² = 3

x = ±√3

Therefore, the zeroes of the given polynomial are √3 and -√3.

Relationship between the zeroes and coefficients :-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x coefficient/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient