find the zeross of the polynomial x2-3 and verify the relationship between the zeros and coefficients
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Answered by
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Step-by-step explanation:
x²-3 = 0
x² = 3
x = ±√3
Therefore, the zeroes of the given polynomial are √3 and -√3.
Relationship between the zeroes and coefficients :-
Sum of zeroes = √3+(-√3) = √3-√3
= 0 = -x coefficient/x² coefficient
Product of zeroes = (√3)(-√3)
= -(√3)² = -3/1 = constant/x² coefficient
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0
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