Question

Find the zerp of polynomial p(x)=(x-2)2-(x+2)2

Answer 1

Step-by-step explanation:

(x-2)²-(x+2)²

(x-2-x-2)(x-2+x+2)

(-4)(2x)

-8x

zeroes of polynomial so p(x)=0

-8x=0

so x is zero

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